【題目】某學(xué)校要建造一個面積為10000平方米的運動場如圖,運動場是由一個矩形ABCD和分別以AD、BC為直徑的兩個半圓組成跑道是一條寬8米的塑膠跑道,運動場除跑道外,其他地方均鋪設(shè)草皮已知塑膠跑道每平方米造價為150元,草皮每平方米造價為30元

1設(shè)半圓的半徑OA=r,設(shè)建立塑膠跑道面積S與r的函數(shù)關(guān)系Sr

2由于條件限制r∈[30,40],問當(dāng)r取何值時,運動場造價最低?最低造價為多少?精確到元

【答案】見解析

【解析】1塑膠跑道面積;S=π[r2r-82]+8××2=+8πr-64π

∵πr2<10000,∴0<r<

1設(shè)運動場的造價為y元,y=150×+30×

=300000+120×7680π

fr+8πr,∵f′r=8π,當(dāng)r∈[30,40]時,f′r<0,

∴函數(shù)y=300000+120×-7680π在[30,40]上為減函數(shù)

∴當(dāng)r=40時,ymin≈636510,即運動場的造價最低為636510元

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