對(duì)于數(shù)對(duì)序列P(a1,b1),(a2,b2),…,(an,bn),記T1(P)=a1+b1,Tk(P)=bk+max{Tk-1(P),a1+a2+…+ak}(2≤k≤n),其中max{Tk-1(P),a1+a2+…+ak}表示Tk-1(P)和a1+a2+…+ak兩個(gè)數(shù)中最大的數(shù),
(1)對(duì)于數(shù)對(duì)序列P(2,5),P(4,1),求T1(P),T2(P)的值.
(2)記m為a,b,c,d四個(gè)數(shù)中最小值,對(duì)于由兩個(gè)數(shù)對(duì)(a,b),(c,d)組成的數(shù)對(duì)序列P(a,b),(c,d)和(a,b).(c,d),試分別對(duì)m=a和m=d的兩種情況比較T2(P)和T2()的大小.
(3)在由5個(gè)數(shù)對(duì)(11,8),(5,2),(16,11),(11,11),(4,6)組成的所有數(shù)對(duì)序列中,寫出一個(gè)數(shù)對(duì)序列P使T5(P)最小,并寫出T5(P)的值.(只需寫出結(jié)論).
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