【題目】室溫下,單質(zhì)A、B、C分別為固體、黃綠色氣體、無(wú)色氣體,在合適反應(yīng)條件下,它們可按下面框圖進(jìn)行反應(yīng)。又知E溶液是無(wú)色的。

請(qǐng)回答:

(1)A是________,B是________,C是________(填化學(xué)式)。

(2)反應(yīng)的化學(xué)方程式為____________________________。

(3)反應(yīng)的化學(xué)方程式為____________________________。

(4)反應(yīng)的化學(xué)方程式為______________________。

【答案】(1)Fe Cl2 H2

(2)2Fe+3Cl22FeCl3

(3)Fe+2HCl===FeCl2+H2

(4)2FeCl2+Cl2===2FeCl3

【解析】解答推斷題的關(guān)鍵在于尋找“突破口”。由B為黃綠色的氣體單質(zhì),可知B為Cl2,C為無(wú)色氣體且與Cl2能發(fā)生反應(yīng),則C為H2,E為HCl;由反應(yīng)可以推出,A為排在H前面的金屬,且A為變價(jià)金屬,因此A為Fe。

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