【題目】昆侖玉的成分為鈣鎂硅酸鹽，可簡(jiǎn)單看成是Ca2Mg5Si8O22（OH）2，則其用二氧化硅和金屬氧化物的形式可表示為 ．

【答案】2CaO5MgO8SiO2H2O．

【解析】根據(jù)硅酸鹽改寫成氧化物的形式為：活潑金屬氧化物較活潑金屬氧化物二氧化硅水，同時(shí)要遵循原子守恒，Ca2Mg5Si8O22（OH）2可表示為：2CaO5MgO8SiO2H2O，故答案為2CaO5MgO8SiO2H2O。

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