已知樣本數(shù)據(jù)1,2,4,3,5,下列說法不正確的是( )
A.平均數(shù)是3
B.中位數(shù)是4
C.極差是4
D.方差是2
【答案】分析:要求平均數(shù)只要求出數(shù)據(jù)之和再除以總個數(shù)即可;根據(jù)中位數(shù)的定義可求出;對于極差是最大值與最小值的差;方差是樣本中各數(shù)據(jù)與樣本平均數(shù)的差的平方和的平均數(shù)
解答:解:在已知樣本數(shù)據(jù)1,2,4,3,5中,平均數(shù)是3;
極差=5-1=4;
方差=2.
所以根據(jù)中位數(shù)的定義,中位數(shù)是3,所以B不正確.
故本題選B.
點評:本題考查平均數(shù)和中位數(shù).一組數(shù)據(jù)的中位數(shù)與這組數(shù)據(jù)的排序及數(shù)據(jù)個數(shù)有關(guān),因此求一組數(shù)據(jù)的中位數(shù)時,先將該組數(shù)據(jù)按從小到大(或按從大到。┑捻樞蚺帕,然后根據(jù)數(shù)據(jù)的個數(shù)確定中位數(shù):當(dāng)數(shù)據(jù)個數(shù)為奇數(shù)時,則中間的一個數(shù)即為這組數(shù)據(jù)的中位數(shù);當(dāng)數(shù)據(jù)個數(shù)為偶數(shù)時,則最中間的兩個數(shù)的算術(shù)平均數(shù)即為這組數(shù)據(jù)的中位數(shù).