$\frac{3}{8}$×$\frac{4}{15}$÷$\frac{7}{9}$ | $\frac{5}{6}$+$\frac{6}{7}$×$\frac{1}{6}$ | $\frac{5}{12}$+$\frac{7}{8}$+$\frac{7}{12}$ |
5×6×($\frac{8}{15}$×$\frac{5}{6}$) | $\frac{7}{13}$×$\frac{8}{15}$+$\frac{8}{15}$×$\frac{8}{13}$ | $\frac{5}{7}$×$\frac{3}{16}$×$\frac{2}{5}$×$\frac{8}{3}$. |
分析 (1)先把分?jǐn)?shù)除法轉(zhuǎn)化為分?jǐn)?shù)乘法,然后按照從左往右的順序依次計算;
(2)先算乘法,再算加法;
(3)根據(jù)加法交換律進行簡算;
(4)根據(jù)乘法交換律和結(jié)合律進行簡算;
(5)根據(jù)乘法分配律進行簡算;
(6)根據(jù)乘法交換律和結(jié)合律進行簡算.
解答 解:
(1)$\frac{3}{8}$×$\frac{4}{15}$÷$\frac{7}{9}$ =$\frac{3}{8}$×$\frac{4}{15}$×$\frac{9}{7}$ =$\frac{1}{10}$×$\frac{9}{7}$ =$\frac{9}{70}$ (2)$\frac{5}{6}$+$\frac{6}{7}$×$\frac{1}{6}$ =$\frac{5}{6}$+$\frac{1}{7}$ =$\frac{35}{42}$+$\frac{6}{42}$ =$\frac{41}{42}$ (3)$\frac{5}{12}$+$\frac{7}{8}$+$\frac{7}{12}$ =$\frac{5}{12}$$+\frac{7}{12}$$+\frac{7}{8}$ =1$+\frac{7}{8}$ =1$\frac{7}{8}$ (4)5×6×($\frac{8}{15}$×$\frac{5}{6}$) =(5×$\frac{8}{15}$)×(6×$\frac{5}{6}$) =$\frac{8}{3}$×5 =$\frac{40}{3}$ (5)$\frac{7}{13}$×$\frac{8}{15}$+$\frac{8}{15}$×$\frac{8}{13}$ =($\frac{7}{13}$$+\frac{8}{13}$)×$\frac{8}{15}$ =$\frac{15}{13}$×$\frac{8}{15}$ =$\frac{8}{13}$ (6)$\frac{5}{7}$×$\frac{3}{16}$×$\frac{2}{5}$×$\frac{8}{3}$ =($\frac{5}{7}$×$\frac{2}{5}$)×($\frac{3}{16}$×$\frac{8}{3}$) =$\frac{2}{7}$×$\frac{1}{2}$ =$\frac{1}{7}$ |
點評 本題主要考查學(xué)生依據(jù)四則運算計算順序進行計算,以及運用簡便算法解決問題的能力.
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