Question

3．大于$\frac{1}{6}$而小于$\frac{1}{5}$的分?jǐn)?shù)有無(wú)數(shù)個(gè)．

Answer 1

分析 可以先把$\frac{1}{6}$和$\frac{1}{5}$進(jìn)行通分，變成分母是30，60，90…的分?jǐn)?shù)，發(fā)現(xiàn)這兩個(gè)分?jǐn)?shù)之間有無(wú)數(shù)個(gè)分?jǐn)?shù)．

解答 解：$\frac{1}{6}$=$\frac{5}{30}$=$\frac{10}{60}$=$\frac{15}{90}$…
$\frac{1}{5}$=$\frac{6}{30}$=$\frac{12}{60}$=$\frac{18}{90}$…
發(fā)現(xiàn)：大于$\frac{1}{6}$而小于$\frac{1}{5}$的分?jǐn)?shù)有$\frac{11}{60}$，$\frac{16}{90}$，$\frac{17}{90}$…有無(wú)數(shù)個(gè)．
故答案為：無(wú)數(shù)．

點(diǎn)評(píng) 通過(guò)通分，把分母進(jìn)行擴(kuò)大，發(fā)現(xiàn)任意兩個(gè)不相等的數(shù)之間都有無(wú)數(shù)個(gè)數(shù)．