11.長(zhǎng)征二號(hào)捆綁式火箭推進(jìn)劑以肼(N2H4)作為燃料.NO2作為氧化劑.反應(yīng)生成N2和水蒸氣.已知: 查看更多

 

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長(zhǎng)征二號(hào)捆綁式火箭推進(jìn)劑以肼(N2H4)作為燃料,NO2作為氧化劑,反應(yīng)生成N2和水蒸氣。已知:N2(g) + 2O2(g) =2NO2(g);       △H=+67.7 kJ/mol

N2H4(g) + O2(g) = N2(g) + 2H2O(g);        △H=-534 kJ/mol

下列關(guān)于肼和NO2反應(yīng)的熱化學(xué)方程式中,正確的是

A.2N2H4(g) + 2NO2(g) = 3N2(g) + 4H2O(l);△H=-1135.7 kJ/mol

B.N2H4(g) + NO2(g) = 3/2N2(g) + 2H2O(g);△H=-567.85 kJ/mol

C.N2H4(g) + NO2(g) = 3/2N2(g) + 2H2O(l);△H=-1135.7 kJ/mol

D.2N2H4(g) + 2NO2(g) = 3N2(g) + 4H2O(g); △H=+1135.7 kJ/mol

 

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長(zhǎng)征二號(hào)捆綁式火箭推進(jìn)劑以肼(N2H4)作為燃料,NO2作為氧化劑,反應(yīng)生成N2和水蒸氣。已知:N2(g) + 2O2(g) =2NO2(g);      △H=+67.7 kJ/mol
N2H4(g) + O2(g) = N2(g) + 2H2O(g);       △H=-534 kJ/mol
下列關(guān)于肼和NO2反應(yīng)的熱化學(xué)方程式中,正確的是


  1. A.
    2N2H4(g) + 2NO2(g) = 3N2(g) + 4H2O(l);△H=-1135.7 kJ/mol
  2. B.
    N2H4(g) + NO2(g) = 3/2N2(g) + 2H2O(g);△H=-567.85 kJ/mol
  3. C.
    N2H4(g) + NO2(g) = 3/2N2(g) + 2H2O(l);△H=-1135.7 kJ/mol
  4. D.
    2N2H4(g) + 2NO2(g) = 3N2(g) + 4H2O(g);△H=+1135.7 kJ/mol

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長(zhǎng)征二號(hào)捆綁式火箭推進(jìn)劑以肼(N2H4)作為燃料,NO2作為氧化劑,反應(yīng)生成N2和水蒸氣。已知:
N2(g) + 2O2(g) =2NO2(g); △H=+67.7 kJ/mol
N2H4(g) + O2(g) = N2(g) + 2H2O(g); △H=-534 kJ/mol
下列關(guān)于肼和NO2反應(yīng)的熱化學(xué)方程式中,正確的是
[     ]
A.2N2H4(g) + 2NO2(g) = 3N2(g) + 4H2O(l);△H=-1135.7 kJ/mol
B.N2H4(g) + NO2(g) = 3/2N2(g) + 2H2O(g);△H=-567.85 kJ/mol
C.N2H4(g) + NO2(g) = 3/2N2(g) + 2H2O(l);△H=-1135.7 kJ/mol
D.2N2H4(g) + 2NO2(g) = 3N2(g) + 4H2O(g); △H=+1135.7 kJ/mol

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長(zhǎng)征二號(hào)捆綁式火箭推進(jìn)劑以肼(N2H4)作為燃料,NO2作為氧化劑,反應(yīng)生成N2和水蒸氣。已知:N2(g) + 2O2(g) =2NO2(g);   △H=+67.7 kJ/mol

N2H4(g) + O2(g) = N2(g) + 2H2O(g);        △H=-534 kJ/mol

下列關(guān)于肼和NO2反應(yīng)的熱化學(xué)方程式中,正確的是

A.2N2H4(g) + 2NO2(g) = 3N2(g) + 4H2O(l);△H=-1135.7 kJ/mol

B.N2H4(g) + NO2(g) = 3/2N2(g) + 2H2O(g);△H=-567.85 kJ/mol

C.N2H4(g) + NO2(g) = 3/2N2(g) + 2H2O(l);△H=-1135.7 kJ/mol

D.2N2H4(g) + 2NO2(g) = 3N2(g) + 4H2O(g); △H=+1135.7 kJ/mol

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長(zhǎng)征二號(hào)捆綁式火箭推進(jìn)劑以肼(N2H4)作為燃料,NO2作為氧化劑,反應(yīng)生成N2和水蒸氣。已知:N2(g) + 2O2(g) =2NO2(g);       △H=+67.7 kJ/mol

N2H4(g) + O2(g) = N2(g) + 2H2O(g);        △H=-534 kJ/mol

下列關(guān)于肼和NO2反應(yīng)的熱化學(xué)方程式中,正確的是

A.2N2H4(g) + 2NO2(g) = 3N2(g) + 4H2O(l);△H=-1135.7 kJ/mol

B.N2H4(g) + NO2(g) = 3/2N2(g) + 2H2O(g);△H=-567.85 kJ/mol

C.N2H4(g) + NO2(g) = 3/2N2(g) + 2H2O(l);△H=-1135.7 kJ/mol

D.2N2H4(g) + 2NO2(g) = 3N2(g) + 4H2O(g); △H=+1135.7 kJ/mol

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1―20  DABBC  BCCBD  BCDAC  BBDCB

21.(7分)(1) 硫或S(1分)

(2)A1(OH)­3;(2分)Al3++3HCO===Al(OH)3↓+3CO2↑(2分)

(3)BaCO­­3­,可能含有BaSO4(2分)

(4)2S2+SO+6H+=3S↓+2H2O(2分)

(5)S2、­ SO=AlO、Na+(4分)

22.(14分)

(1)除去沾有的油污(2分)

(2)反應(yīng)速率慢   不利于昌體析出。(2分)增大FeSO4的溶解量(2分)

(3)水浴加熱均勻,溫度容易控制。(2分)

(4)Fe3++2Fe=3Fe2+(2分)

(5)減少FeSO4的損失(2分)

(6)有淺綠色晶體析出(2分)

23.2.物質(zhì)結(jié)構(gòu)與性質(zhì)

(1)CaCl2。(2分)Ca2+[x CCx] 2

(2)(2分)S=C=S(2分)H2S(2分)

(3)Si3N4

(4)4H-+SiO2=SiF4+2H2O(2分)

24.27.(17分)

(1)    (2分)

(2)2NH3(l)NHNH (2分)

(3) ①打開(kāi)止水夾,通入少量氧氣(2分)

②P­2O­5+6OH-=2PO­­43-+3H2O(2分)

③Cu片逐漸溶解,有無(wú)色氣泡產(chǎn)生,溶液由無(wú)色變?yōu)樗{(lán)色(3分)

3Cu+8H++2NO=3Cu2++2NO+4H2O(2分)

(4) ①2NO­2NO+O­2(2分)

②30.7(2分)

 

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