若[1+(r+1)n]=1.則r的取值范圍是 . 查看更多

 

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(2012•上海)若(2x-1)5=a0+a1x+a2x2+a3x3+a4x4+a5x5,則a0+a1+a2+a3+a4+a5=
1
1

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已知首項(xiàng)不為零的數(shù)列{an}的前n項(xiàng)和為Sn,若對(duì)任意的r,t∈N*,都有
Sr
St
=( 
r
t
 )2

(Ⅰ)判斷數(shù)列{an}是否為等差數(shù)列,并證明你的結(jié)論;
(Ⅱ)若數(shù)列{bn}的第n項(xiàng)bn是數(shù)列{an}的第bn-1項(xiàng)(n≥2,n∈N*),且a1=1,b1=3,求數(shù)列{bn}的前n項(xiàng)和Tn

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已知f1(x)=3|x-1|,f2(x)=a•3|x-2|,(x∈R,a>0).函數(shù)f(x)定義為:對(duì)每個(gè)給定的實(shí)數(shù)x,f(x)=
f1(x)    f1(x)≤f2(x) 
f2(x)    f1(x)>f2(x) 

(1)若f(x)=f1(x)對(duì)所有實(shí)數(shù)x都成立,求a的取值范圍;
(2)設(shè)t∈R,t>0,且f(0)=f(t).設(shè)函數(shù)f(x)在區(qū)間[0,t]上的單調(diào)遞增區(qū)間的長(zhǎng)度之和為d(閉區(qū)間[m,n]的長(zhǎng)度定義為n-m),求
d
t
;
(3)設(shè)g(x)=x2-2bx+3.當(dāng)a=2時(shí),若對(duì)任意m∈R,存在n∈[1,2],使得f(m)≥g(n),求實(shí)數(shù)b的取值范圍.

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已知首項(xiàng)不為零的數(shù)列{an}的前n項(xiàng)和為Sn,若對(duì)任意的r,t∈N*,都有
(Ⅰ)判斷數(shù)列{an}是否為等差數(shù)列,并證明你的結(jié)論;
(Ⅱ)若數(shù)列{bn}的第n項(xiàng)bn是數(shù)列{an}的第bn-1項(xiàng)(n≥2,n∈N*),且a1=1,b1=3,求數(shù)列{bn}的前n項(xiàng)和Tn

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已知首項(xiàng)不為零的數(shù)列{an}的前n項(xiàng)和為Sn,若對(duì)任意的r,t∈N*,都有
Sr
St
=( 
r
t
 )2

(Ⅰ)判斷數(shù)列{an}是否為等差數(shù)列,并證明你的結(jié)論;
(Ⅱ)若數(shù)列{bn}的第n項(xiàng)bn是數(shù)列{an}的第bn-1項(xiàng)(n≥2,n∈N*),且a1=1,b1=3,求數(shù)列{bn}的前n項(xiàng)和Tn

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