解:(1)函數(shù)的圖象經(jīng)過(0,0)點(diǎn),
∴c=0.
又圖象與x軸相切于(0,0)點(diǎn),
y'=3x2-6x+b,
∴0=3×02-6×0+b,
解得b=0.
(2)y=x3-3x2,
y'=3x2-6x,
當(dāng)x<2時,y'<0;當(dāng)x>2時,y'>0.
則當(dāng)x=2時,函數(shù)有極小值-4.
(3)y'=3x2-6x<0,
解得0<x<2,
∴遞減區(qū)間是(0,2).
分析:(1)根據(jù)函數(shù)的圖象經(jīng)過(0,0)點(diǎn)得到c=0,又圖象與x軸相切于(0,0)點(diǎn),令導(dǎo)函數(shù)在x=0處的值為0得到b的值.
(2)求出導(dǎo)函數(shù),令導(dǎo)函數(shù)為0得到根,判斷根左右兩邊的符號,求出函數(shù)的極小值.
(3)求出導(dǎo)函數(shù),令導(dǎo)函數(shù)小于0得到x的范圍,寫出區(qū)間即為函數(shù)的遞減區(qū)間.
點(diǎn)評:解決函數(shù)的單調(diào)性、極值、最值問題,常利用的工具是函數(shù)的導(dǎo)函數(shù).但要注意導(dǎo)函數(shù)在極值點(diǎn)處的值為0是此點(diǎn)為極值點(diǎn)的必要條件而不是充要條件.