Question

操作：小明準(zhǔn)備制作棱長(zhǎng)為1cm的正方體紙盒，現(xiàn)選用一些廢棄的圓形紙片進(jìn)行如下設(shè)計(jì)：

 

發(fā)現(xiàn)：（1）方案一中的點(diǎn)A、B恰好為該圓一直徑的兩個(gè)端點(diǎn)．你認(rèn)為小明的這個(gè)發(fā)現(xiàn)是否正確，請(qǐng)說明理由．

（2）小明通過計(jì)算，發(fā)現(xiàn)方案一中紙片的利用率僅約為38.2%．請(qǐng)幫忙計(jì)算方案二的利用率，并寫出求解過程．

    探究：（3）小明感覺上面兩個(gè)方案的利用率均偏低，又進(jìn)行了新的設(shè)計(jì)（方案三），請(qǐng)直接寫出方案三的利用率．

 

Answer 1

發(fā)現(xiàn)：（1）小明的這個(gè)發(fā)現(xiàn)正確．················································································ 1分

理由：解法一：如圖一：連接AC、BC、AB，∵AC＝BC＝，AB＝

∴AC²+BC²＝AB²   ∴∠BAC＝90°，················································· 2分

∴AB為該圓的直徑．····································································· 3分

解法二：如圖二：連接AC、BC、AB．易證△AMC≌△BNC，∴∠ACM＝∠CBN．

又∵∠BCN＋∠CBN＝90°，∴∠BCN＋∠ACM＝90°，即∠BAC＝90°，······ 2分

∴AB為該圓的直徑．············································································ 3分

 

 

 

 

 

 

 

 

（2）如圖三：易證△ADE≌△EHF，∴AD＝EH＝1．······················································ 4分

∵DE∥BC，∴△ADE∽△ACB，∴＝∴＝，∴BC＝8．································ 5分

∴S_△ACB＝16．················································································································ 6分

∴該方案紙片利用率＝×100%＝×100%＝37.5% ······························ 7分

探究：（3）············································································································ 9分

 

解析:略