AC
分析:根據(jù)溶液的均一性和溶質(zhì)質(zhì)量分數(shù)的計算公式分析解答,溶質(zhì)質(zhì)量分數(shù)=
×100%
解答:A、溶液具有均一性,所以從溶質(zhì)質(zhì)量分數(shù)為20%的100g氯化鈉溶液中取出10g溶液,則取出的溶液中溶質(zhì)的質(zhì)量分數(shù)不變,說法正確;
B、根據(jù)溶質(zhì)質(zhì)量分數(shù)=
×100%=
×100%<16%,故說法錯誤;
C、根據(jù)溶質(zhì)質(zhì)量分數(shù)=
×100%=
×100%=80%,故說法正確;
D、根據(jù)溶質(zhì)質(zhì)量分數(shù)=
×100%=
×100%=16.7%,故說法錯誤;
故選AC
點評:記住溶液的均一性,會運用溶質(zhì)質(zhì)量分數(shù)=
×100%計算公式求溶液中溶質(zhì)的質(zhì)量分數(shù)是解答本題關(guān)。