Question

下表是的密度ρ和溶質(zhì)的質(zhì)量分?jǐn)?shù)的對(duì)照表，查表計(jì)算下列各題：

(1)1mL質(zhì)量分?jǐn)?shù)為98％的濃硫酸中含純硫酸________g．

(2)配制質(zhì)量分?jǐn)?shù)為20％的硫酸450g，需要60％的硫酸________mL．

(3)將1L質(zhì)量分?jǐn)?shù)為98％的濃硫酸稀釋成質(zhì)量分?jǐn)?shù)為30％的稀釋酸需加水________mL．

Answer 1

答案：1.80#1.8;100;4170.7
解析：

(1)純硫酸的質(zhì)量=濃硫酸溶液的質(zhì)量×質(zhì)量分?jǐn)?shù)=濃硫酸的密度×體積×質(zhì)量分?jǐn)?shù)． m=1.84g／cm3×1mL×98％=1.80g (2)設(shè)配制質(zhì)量分?jǐn)?shù)為20％的硫酸450g，需60％的硫酸的體積為x． 450g×20％=x·1.50g／mL×60％ 解得　x=100mL (3)設(shè)需加水的體積為x． 1000mL×1.84g／mL×98％=(1000mL×1.84g／mL＋x)×30％ 解得　x=4170.7mL